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2C8H18 + 25O2 → 16CO2 + 18H2O Assuming gasoline is 91.0% isooctane, with a density of...

2C8H18 + 25O2 → 16CO2 + 18H2O

Assuming gasoline is 91.0% isooctane, with a density of 0.692 g/mL, what is the theoretical yield (in grams) of CO2 produced by the combustion of 1.39 x 1010 gallons of gasoline (the estimated annual consumption of gasoline in the U.S.)? Remember, there are 3.785 liters in 1 gallon and assume that isooctane is the only carbon containing component of gasoline.

Scientific notation can be entered as follows: 1.23 x 1023 = 1.23E23

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