Question

Language is in C. Need help troubleshooting my code

Goal of code:

* Replace strings with a new string.

* Append an s to the end of your input string if it's not a keyword.

* Insert a period at the end, if you have an empty input string do not insert a period

Problems:

//Why does my code stop at only 2 input strings

//If I insert a character my empty string case works but it's still bugged where no string is printed at all besides the period.

//Edge case for consecutive key words? Doing str1 str1 results in just "is str1 is str1s"

I've rewritten the input strings in case of academic integrity issues.

int main(int argc, char** argv) {

    int counter = 0;

    for(int i = 0; i

    counter = i;

        if(strcmp(argv[i],"str1")==0){

            printf("%s", "is str1 ");

            if(strcmp(argv[i+1],"str2")==0){

                printf("%s\n", "is str2");

            }

            else if(strcmp(argv[i+1],"str3")==0){

                printf("%s\n", "is str3");

            }

            else if(strcmp(argv[i+1],"str 4")==0){

                printf("%s\n", "is str4");

            }

            else{

                    printf("%s\n",strncat(argv[i+1],"s",1));

            }

        }

        if (*argv[0] != '\0'){

            printf("%s\n", ".");

        }

        */

        printf("%d\n",counter);

    }   

    return 0;

}

Answer 1

I didn't get much of your program but the issue I found is indexing.

argv[0] holds the name of the program and argv[1] points to the first command line argument and argv[n] gives the last argument. If no argument is supplied, argc will be 1.

Output

Code

#include <stdio.h>

#include <stdlib.h>

#include<string.h>

int main(int argc, char **argv)

{

   if(argc<=1){

      printf("No arguments provided!!\n");

      return 0;

   }

   int count = argc-1;

   if(strcmp(argv[1],"str1")==0){ //checking equal to str1

      printf("str1 found!!");

   }

   if(count>1){ //concat s

      printf(strcat(argv[2],"s"));

      printf("\n");

   }

   if(count>2){

      if(argv[3][0]!='\0'){ //concat dot

         printf(strcat(argv[3],"."));

         printf("\n");

      }

   }

   if(count>3){

      printf("%s\n",argv[4]);

   }

   if(count>4){

      printf("%s\n",argv[5]);

   }

   if(count>5){

      printf("%s\n",argv[6]);

   }

   return 0;

}