Find the z-score, to the nearest hundredth, that satisfies the given condition. 0.166 square unit of the standard normal distribution is to the left of z.
solution:
Using standard normal table,
P(Z < z) = 0.166
= P(Z < z) = 0.166
= P(Z <-0.97 ) = 0.166
z = -0.97 Using standard normal table,
Find the z-score, to the nearest hundredth, that satisfies the given condition. 0.166 square unit of...
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