Question

#2

near the ground at the north magnetic pole, the earth’s magnetic field is directed downward vertically and has a strength of 0.57 G. An electron at the north pole is projected from the ground into this magnetic field with a velocity of 1.4 km/s vertically upward and 1.9 km/s horizontally to your right.

A) find the magnitude of the force acting on this electron

B) find the electron’s acceleration (magnitude and direction)

Answer 1

- B -0.579 (-) ū - 14 komy's +1.9 km/s 1 B q = - 1-6 x 10-la e groura A) IG= 10-4 T. - B = 0.57x10h T (*) u a 1.4 x 103 m/s Ŕ + 1.9 x 103 m/s? qGxB) = -1.6 x 1073 [(1.4x18 k + 1.9 x 1037 ) x (0.57 710 (-))] l'emot [(4x 0 257 % 10°) (* *-) + .970% 20-5 3464 (1 **)] = -1-6x19x0-57 x 10 19 +3=4 i = -1-7328 x 1020 N 3 Magnitude of hore Fla 1-7328 x 10-20 ~ Acceleratron tal (Fyn a 1.73 28 * 10 20 9.B1x 1031 = 1.9021 x 100 mm/s2 Direction of acceleration au same as that of force re, in the y direction perpendiculas to direction of magnetic field and direction of relocity of electron