Question

A sample of blood is placed in a centrifuge of radius 12.0 cm. The mass of a red blood cell is 3.0 ✕ 10^-16 kg, and the magnitude of the force acting on it as it settles out of the plasma is 4.0 ✕10^-11 N. At how many revolutions per second should the centrifuge be operated?
rev/s

A sample of blood is placed in a centrifuge of radius 12.0 cm. The mass of a red blood cell is 3.0 x 10-16 kg, and the magnitude of the force acting on it as it settles out of the plasma is 4.0 x 10-11 N. At how many revolutions per second should the centrifuge be operated? rev/s C

Answer 1

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Given that,

Centripetal force,

F = 4 x 10-11 N

Radius, r = 12 cm =0.12 m

Mass of red blood cells,

m = 3 x 10-16 kg

Therefore, angular speed is given by:

Fe=mru?

mr

.W = V mr 4 x 10-11 N V3 x 10-16 kg x 0.12 m

::w= V1111111.1 rad/s

:.w= 1054.1 rad/s

We have, 1 rev/s = 2$\boldsymbol{\pi}$ rad/s

..w = 1054.1 rad/s = 1054.1 x rev/s

::w= 167.76 rev/s

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