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When 3.741 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 12.65 grams...


When 3.741 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 12.65 grams of CO2 and 2.589 grams of H2O were produced.

In a separate experiment, the molar mass of the compound was found to be 78.11g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon.

  • Enter the elements in the order presented in the question.
    empirical formula =
    molecular formula =
0 0
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Answer #1

mol (or = 12.65 - = 0.2875 44 mcl. mol = 0.2685 mel mel 120 = 2.389 = 0.1434 mil 18 mol ne 0.2976. mel Divide by deart Jadus

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