Naphthalene undergoes electrophilic aromatic substitution predominately at the 1-position (α-position) to give the more Electrophile (here I+) attack at the 1- position of Naphthalene gives an intermedaite that is represented by 7 resonance contributors of which 4 leave the aromaticity of the other ring intact.
1 is 1 st position, 2 is 2 nd position.
When naphthalene undergoes an irreversible electrophilic aromatic substitution, the major product is the kinetic product, which...
a See page 1127 13 Question (3 points) When naphthalene undergoes an irreversible electrophilic aromatic substitution, the major product is the kinetic product, which proceeds through the most stable arenium ion intermediate. With this in mind, draw the curved arrow mechanism for the first step of the electrophilic aromatic substitution of naphthalene with the acylium ion generated from acetyl chloride and AlClg, Then draw the curved arrows and a resonance structure in step 2 with an unbroken benzenoid ring.Draw all...
Pyrrole undergoes nitration by electrophilic aromatic substitution. Complete the mechanism by drawing curved arrows, the structure of the charged intermediate, and the structure of the major uncharged product. Omit electron lone pairs and bases. Trole undergoes nitration by electrophilic aromatic substitution. Complete the mechanism by drawing curved arrows, the structure of the charged intermediate, and the structure of the major uncharged product. Omit electron lone pairs and bases.
+ H+ Electrophilic aromatic substitution is a two-step process. In the first step an electrophile, here generically shown as Y , reacts with the aromatic ring to form a resonance-stabilized carbocation intermediate. In the second step, loss of a proton from the site of attack restores aromaticity to the ring and completes the reaction. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions no XT + H H- A
The electrophilic aromatic substitution of isopropylbenzene with FeBr3, Br2 gives 1-bromo-4-isopropylbenzene. Complete the curved-arrow mechanism below, beginning with formation of the active brominating reagent. Remember to include lone pairs and formal charges where appropriate. The electrophilic aromatic substitution of isopropylbenzene with FeBr3, Br2 gives 1-bromo-4-isopropylbenzern Complete the curved-arrow mechanism below, beginning with formation of the active brominating reagent. Remember to include lone pairs and formal charges where appropriate. Draw the pro Overall transformation (ungraded) bromine and FeBr3 Include curved arrow(s)....
250 ChemActivity 29 Electrophilic Aromatic Substitution no ChemActivity 29 Part A: Electrophilic Aromatic Substitution (What products are formed when a strong electrophile is added to benzene?) Model 1: (review) Electrophilic Addition of HCI Rani o g cyclohexene carbocation intermediate Run 2 U X benzene This product carbocation intermediate DOES NOT Critical Thinking Questions 1 For Rxn I (above) draw curved arrows showing the mechanism of electrophilic addition of HCl. Include an appropriate carbocation intermediate in the box above. Figure 1:...
Complete the mechanism for the electrophilic aromatic substitution of trifluorobenzene. Do not bother placing all of the lone pairs of electrons on the F atoms, but be sure to place them on all other atoms as needed. Do not draw curved arrows between the resonance structures.
a) Complete the generic mechanism for an electrophilic aromatic substitution (EAS) reaction using El as the electrophile and show how the sigma complex is resonance stabilized. Use curved arrows to show the mechanism and the conversion between resonance structures. Make sure to add any missing charges. Note the use of a generic base in the last step. b) Label the reaction coordinate diagram for a typical EAS reaction shown below by correctly placing the letter for each structure on the...
1,3-Butadiene undergoes an electrophilic addition with HBr. Complete the steps in the mechanism to produce the product shown1) Add curved arrows for the first step. 2) Draw both the organic and inorganic intermediate species. Include all nonbonding electrons and charges. Draw a curved arrow to convert the intermediate into the product shown.
For question 2) Electrophiles for the electrophilic aromatic substitution reactions have to be very strong to react with the stable aromatic rings. A nitronium ion is needed for nitration of aromatic rings. Complete the mechanism of the formation of the nitronium ion from concentrated nitric acid in concentrated sulfuric acid. Question 2 of 45 Add curved arrows. Hint Map Complete the structure and add curved arrows to show the formation of the nitronium. Draw the products. Previous Check Answer 0...
The trisubstituted product below was synthesized in one step from an electrophilic aromatic substitution of a disubstituted benzene ring. Draw the disubstituted benzene starting material that would give this regioisomeric product. The trisubstituted product below was synthesized in one step from an electrophilic aromatic substitution of a disubstituted benzene ring. Draw the disubstituted benzene starting material that would give this regioisomeric product. HOOC COOH NO2