Question we have degree of freedom = n-1 = 6-1 = 5

using t distribution table with degree of freedom 5 and significance level of 0.05, we get

t critical = 2.57

(A) formula for the confidence interval is given as setting the given values, we get this gives us Required confidence interval is (58.46,81.54) (rounded to two decimals)

(b) Margin of error = setting the given values, we get

margin of error = (rounded to two decimals)

We calculate confidence interval for the population mean, So option D is correct regarding the interpretation of confidence interval.

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