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In each reaction box, place the best reagent and conditions from the list below.


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Answer #1
Concepts and reason

The concept used to solve this problem is by using the given reagents, possible products will be formed in each step and then label it exactly in the given boxes in order to form the exact product.

Here, the starting reactant is vinylcyclohexane and the final product is prop-1-yn-1-ylcyclohexane.

Fundamentals

Sodium amide ( NaNH2{\rm{NaN}}{{\rm{H}}_2} ) is used as base, which abstract the proton.

Hydroboration in the presence of tetrahydrofuran followed by the oxidation gives a primary alcohol.

Bromine molecule is used for bromination of alkene. Trans addition takes place.

Addition of HBr to the double bond forms an alkyl bromide.

Potassium tertiary butoxide is a sterically hindered base.

Ozonolysis of the double bond forms the carbonyl compounds.

The reaction is as follows:

BI2
O-01
Br
vinylcyclohexane
(1,2-dibromoethyl)cyclohexane

The reaction is as follows:

Olo
excess NaNH2
Br
(1,2-dibromoethyl)cyclohexane
ethynylcyclohexane

The reaction is as follows:

NaNH)
obavo
cyclohexylethyn-1-ide
ethynylcyclohexane

The reaction is as follows:

=CH
=c
o
CH3Br
cyclohexylethyn-1-ide
prop-1-yn-1-ylcyclohexane

Ans:

The best reagents that are used for the conversion of vinylcyclohexane to prop-1-yn-1-ylcyclohexane are as follows:

1)
Brz
-EC-CH
excess NaNH2
2)
3)
CH3BT

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Answer #2
Concepts and reason

The concept used to solve this problem is by using the given reagents, possible products will be formed in each step and then label it exactly in the given boxes in order to form the exact product.

Here, the starting reactant is vinylcyclohexane and the final product is prop-1-yn-1-ylcyclohexane.

Fundamentals

Sodium amide ( NaNH2{\rm{NaN}}{{\rm{H}}_2} ) is used as base, which abstract the proton.

Hydroboration in the presence of tetrahydrofuran followed by the oxidation gives a primary alcohol.

Bromine molecule is used for bromination of alkene. Trans addition takes place.

Addition of HBr to the double bond forms an alkyl bromide.

Potassium tertiary butoxide is a sterically hindered base.

Ozonolysis of the double bond forms the carbonyl compounds.

The reaction is as follows:

BI2
O-01
Br
vinylcyclohexane
(1,2-dibromoethyl)cyclohexane

The reaction is as follows:

Olo
excess NaNH2
Br
(1,2-dibromoethyl)cyclohexane
ethynylcyclohexane

The reaction is as follows:

NaNH)
obavo
cyclohexylethyn-1-ide
ethynylcyclohexane

The reaction is as follows:

=CH
=c
o
CH3Br
cyclohexylethyn-1-ide
prop-1-yn-1-ylcyclohexane

Ans:

The best reagents that are used for the conversion of vinylcyclohexane to prop-1-yn-1-ylcyclohexane are as follows:

1)
Brz
-EC-CH
excess NaNH2
2)
3)
CH3BT

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