In each reaction box, place the best reagent and conditions from the list below.
The concept used to solve this problem is by using the given reagents, possible products will be formed in each step and then label it exactly in the given boxes in order to form the exact product.
Here, the starting reactant is vinylcyclohexane and the final product is prop-1-yn-1-ylcyclohexane.
Sodium amide ( ) is used as base, which abstract the proton.
Hydroboration in the presence of tetrahydrofuran followed by the oxidation gives a primary alcohol.
Bromine molecule is used for bromination of alkene. Trans addition takes place.
Addition of HBr to the double bond forms an alkyl bromide.
Potassium tertiary butoxide is a sterically hindered base.
Ozonolysis of the double bond forms the carbonyl compounds.
The reaction is as follows:
The reaction is as follows:
The reaction is as follows:
The reaction is as follows:
Ans:The best reagents that are used for the conversion of vinylcyclohexane to prop-1-yn-1-ylcyclohexane are as follows:
The concept used to solve this problem is by using the given reagents, possible products will be formed in each step and then label it exactly in the given boxes in order to form the exact product.
Here, the starting reactant is vinylcyclohexane and the final product is prop-1-yn-1-ylcyclohexane.
Sodium amide ( ) is used as base, which abstract the proton.
Hydroboration in the presence of tetrahydrofuran followed by the oxidation gives a primary alcohol.
Bromine molecule is used for bromination of alkene. Trans addition takes place.
Addition of HBr to the double bond forms an alkyl bromide.
Potassium tertiary butoxide is a sterically hindered base.
Ozonolysis of the double bond forms the carbonyl compounds.
The reaction is as follows:
The reaction is as follows:
The reaction is as follows:
The reaction is as follows:
Ans:The best reagents that are used for the conversion of vinylcyclohexane to prop-1-yn-1-ylcyclohexane are as follows:
In each reaction box, place the best reagent and conditions from the list below. In each...
In each reaction box, place the best reagent and conditions from the list below. CH3 HBr CH3Br Br2 H2, Lindlar catalyst bromocyclohexane BH3 THF H202, NaOH, H20 H20, H2SO4 excess NaNH2 CH3CH2Br SOC
In each reaction box, place the best reagent and conditions from the list below. CH3 2) 3) H2, Lindlar catalyst H2O, H2SO4 CH3CH2Br Br2 bromocyclohexane BH3/THF SOCl2 excess NaNH2 HBr CH3Br H2O2, NaOH, H2O
In each reaction box, place the best reagent and conditions from the list below. You have the wrong reagent for the final step. An oxidizing agent is necessary to convert the boron functional group into an enol, which will tautomerize to the aldehyde. 1) Br2 DEDY 2) excess NaNH2, then H20 3) BH3/THF 2 equiv. NaNH2 H2, Lindlar catalyst bromocyclohexane HBr H20, H2SO4, HgSO4 NaBH4 CH3Br CH3CH2Br H2O2, NaOH, H20 SOCI2
In each reaction box, place the best reagent and Conditions from the list below. H C C H Br Br H2, Lindlar catalyst H20, H2SO4, Hgso4 CH3CH2Br HBr 1-equiv BH3/THF HBr 2-equiv CH3CH2CH2Br CH3Br H202/NaOH Br2 1-equiv NaOH NaNH2 Br2 2-equiv
In each reaction box, place the best reagent and conditions from the list below. In each reaction box, place the best reagent and conditions from the list below. 2 equiv. NaNHz excess NaNH2 CH3Br H20, H2SO4, HgSO4 Na, NH3 (1) H2O2, NaOH, H2O NaBH4 HBr Br2 CH3CH2Br H2. Lindlar catalyst BH3/THF PBr3
In each reaction box, place the best reagent and conditions from the list below. -C50-CH 00 H2, Lindlar catalyst bromocyclohexane HBr H20, H2SO4 BH3/THE CH3Br CH3CH2Br SOCl2 H2O2, NaOH, H20 Br2 excess NaNH2
In each reaction box, place the best reagent and conditions from the list below. In each reaction box, place the best reagent and conditions from the list below. O H2, Lindlar catalyst bromocyclohexane BH3/THE H20, H2SO4 HBO CH3Br H202, NaOH, H20 CH3CH Br SOCI Brz excess NaNH2
In each reaction box, place the best reagent and conditions from the list below. O OY NaBHA SOCI CH3CH2Br 2 equiv. NaNH2 BH/THF HBr Brz H2O3, NaOH, H2O bromocyclohexane H2. Lindlar catalyst H20, H2SO4, HgSO4 CH3Br excess NaNHz, then H20
In each reaction box, place the best reagent and conditions from the list below. OOY NaBHA CH3CH2Br 2 equiv. NaNH2 Brz BHY/THF H2O2. NaOH, H20 SOCI HBR H2. Lindlar catalyst H20, H2SO4, HgSO4 bromocyclohexane excess NaNH2, then H2O CH3Br
In each reaction box, place the best reagent and conditions from the list below. mu have the right idea for generating an alkyne in the first two steps. Remember that a primary alkyne also reacts with NaNH2 to form the alkylide ion, so with only two equivalents of NaNH2 you will d up with a mixture of some alkylide anion, some unreacted vinyl bromide and probably some unreacted vicinal dibromide. Br2 O 2 equiv. NaNH2 OY BH3/THF 3) 4) H2O2,...