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3. A sample of 20 silver dollar coins is weighed. The mean of the sample is 8.0710 g and the (l point) standard deviation of the sample is 0 0411 g Construct a 95% confidence interval estimate of the mean weight of all the coins 7.6615 g H84746 g 8.0518 g< H <8.0902 g 8.0447 g<p8.0973 g 8.0329 g<p<8.1121 g 4. To determine the weight of plastic discarded by households, a sample size of 62 weights are (l point) measured and are found to have a mean of 1.911 lb and a standard deviation of 1.065 Ib. Construct a 99% confidence interval estimate of the mean weight of plastic discarded by all households 0.846 lb2.976 lb O 1.892 lb < < 1 .930 lb 1.551 IbCl < 2.271 lb 0 1 640 lb < 2.1 821b
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sample mean sample size sample std deviation x= 20.00 standard errror of means s,-s/in- 0.009 for 95% CI; and 19 degree of freedom, value of t margin of error E-t std error lower confidence bound-sample mean-margin of error = Upper confidence bound-sample mean+margin of error- 2.0930 0.019 8.0518 8.0902

from above 95% CI : 8.0518 < mu <8.0902

4)

sample mean sample size sample std deviation 1.911 62.00 1.065 x= standard errror of meaS-S/Vn-0.135 for 99% CI; and 61 degree of freedom, value of t margin of error E-t std error lower confidence bound-sample mean-margin of error Upper confidence bound-sample mean+margin of error- 2.6590 1.5514 2.2706

99% CI : 1.551 < mu <2.271

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