Arrange the following heat quantities from smallest to largest.
a. BTU
b. joule
c. calorie
d. kilocalorie
e. therm
We have the following metric conversions between Btu, joule, calorie, Kcal and Therm:
1 calorie \(=4.2 \mathrm{~J}\)
I Kcal = 1000 calorie
1 calorie \(=0.00397\) Btu
\(\mid \mathrm{Kcal}=3.97 \mathrm{Btu}\)
I Therm \(=100,000\) Btu
From the above conversions, we can conclude that:
\(J<\) calorie \(<\) Btu \(<\) Kcal \(<\) Therm
Thus, the solution to the problem is \(\mathrm{b}<\mathrm{c}<\mathrm{a}<\mathrm{d}<\mathrm{e}\).