Arrange the following heat quantities from smallest to largest.a. BTUb. joulec. caloried....

We have the following metric conversions between Btu, joule, calorie, Kcal and Therm:

1 calorie \(=4.2 \mathrm{~J}\)

I Kcal = 1000 calorie

1 calorie \(=0.00397\) Btu

\(\mid \mathrm{Kcal}=3.97 \mathrm{Btu}\)

I Therm \(=100,000\) Btu

From the above conversions, we can conclude that:

\(J<\) calorie \(<\) Btu \(<\) Kcal \(<\) Therm

Thus, the solution to the problem is \(\mathrm{b}<\mathrm{c}<\mathrm{a}<\mathrm{d}<\mathrm{e}\).