Determine Vo1 and Vo2 for the networks of Fig. 2.159.
FIG. 2.159
(a)
Draw the circuit diagram:
Figure 1
The silicon (Si) diode voltage is 0.7 V
The silicon diode is forward biased and is in the ON state.
Apply Kirchhoff's voltage law for loop 1 , to obtain the vo1.
vo1 =12 V-0.7 V
=11.3 V
The Gallium Arsenide (GaAs) diode voltage is \(1.2 \mathrm{~V}\) Apply Kirchhoff's voltage law for loop 2 , to obtain the \(v_{o 2}\). \(v_{o 2}=1.2 \mathrm{~V}\)
(b)
Draw the circuit diagram:
Figure 2
The silicon (Si) diode voltage is \(0.7 \mathrm{~V}\)
The Germanium (Ge) diode voltage is \(0.3 \mathrm{~V}\)
Here, the Germanium (Ge) diode is in reverse biased state so it is in the OFF state.
Apply Kirchhoff's voltage law for loop 1 , to obtain the \(v_{o 1}\). \(v_{o 1}=0 \mathrm{~V}\)
Here, the silicon (Si) diode is in reverse biased state so it is in the OFF state.
Apply Kirchhoff's voltage law for loop 2 , to obtain the \(v_{o 2}\). \(v_{o 2}=0 \mathrm{~V}\)