Problem

A particle is traveling along the parabolic path y = 0.25x2. If x = (2t2) m, where t is in...

A particle is traveling along the parabolic path y = 0.25x2. If x = (2t2) m, where t is in seconds, determine the magnitude of the particle’s velocity and acceleration when t = 2 s.

Step-by-Step Solution

Solution 1

Component of the particle position is

Given

Velocity of the particle along the axis is expressed as

Accordingly, we have from

So, we have

Velocity of the particle along the axis is expressed as

Given

By differentiating the above the relation, we have

By substituting and the value of into the above relation, we have

Magnitude of the particle velocity at is expressed as

By substituting the values of the parameters into the above relation, we have

Magnitude of the particle velocity at is

Acceleration of the particle along the axis is expressed as

Accordingly, we have from

Acceleration of the particle along the axis is expressed as

Accordingly, we have from

When:

Magnitude of the particle acceleration at is expressed as

By substituting the values of the parameters into the above relation, we have

Magnitude of the particle acceleration at is

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