A particle is traveling along the parabolic path y = 0.25x2. If x = (2t2) m, where t is in seconds, determine the magnitude of the particle’s velocity and acceleration when t = 2 s.
Component of the particle position is
Given
Velocity of the particle along the axis is expressed as
Accordingly, we have from
So, we have
Velocity of the particle along the axis is expressed as
Given
By differentiating the above the relation, we have
By substituting and the value of into the above relation, we have
When:
Magnitude of the particle velocity at is expressed as
By substituting the values of the parameters into the above relation, we have
Magnitude of the particle velocity at is
Acceleration of the particle along the axis is expressed as
Accordingly, we have from
Acceleration of the particle along the axis is expressed as
Accordingly, we have from
When:
Magnitude of the particle acceleration at is expressed as
By substituting the values of the parameters into the above relation, we have
Magnitude of the particle acceleration at is