In figure 23-45, a small circular hole of radius R=1.80 cm has been cut in the middle of an infinite, flat, nonconducting surface that has uniform charge density σ= 4.5 pC/m2. A z axis, with its origin at the hole's center, is perpendicular to the surface. In unit-vector notation, what is the electric field at point P at z=2.56 cm? (Hint: see Eq. 22-26 and use superposition.)
In figure 23-45, a small circular hole of radius R=1.80 cm has been cut in the middle of an infinite,
In the figure below, a small circular hole of radius R = 1.80 cm
has been cut in the middle of an infinite, flat, nonconducting
surface that has uniform charge density σ = 6.70 pC/m2.
A z-axis, with its origin at the hole's center, is perpendicular to
the surface. In unit-vector notation, what is the
electric field at point P at z = 2.68 cm? (Hint: See Eq. 22-26 and
use superposition.)
_________N/C
In the figure a small circular hole of radius R = 2.23
cm has been cut in the middle of an infinite, flat, nonconducting
surface that has a uniform charge density σ = 4.23 pC/m2. A zaxis,
with its origin at the hole's center, is perpendicular to the
surface. What is the magnitude of the electric field at point P at
z = 2.79 cm?
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1. A very long, uniformly charged cylinder has radius R and charge density \rho. Determine the electric field of this cylinder inside (r<R) and outside (r>R)2. A large, flat, nonconducting surface carries a uniform surface charge density σ. A small circular hole of radius R has been cut in the middle of the sheet. Determine the electric field at a distance z directly above the center of the hole.3. You have a solid, nonconducting sphere that is inside of, and...
3.12 An infinite, thin, plane sheet of conducting material has a circular hole of radius a cut in it. A thin, flat disc of the same material and slightly smaller radius lies in the plane, filling the hole, but separated from the sheet by a very narrow insulating ring. The disc is maintained at a fixed potential V, while the infinite sheet is kept at zero potential. (a) Using appropriate cylindrical coordinates, find an integral expression involv- ing Bessei functions...
Consider a cylindrical capacitor like that shown in Fig. 24.6. Let d = rb − ra be the spacing between the inner and outer conductors. (a) Let the radii of the two conductors be only slightly different, so that d << ra. Show that the result derived in Example 24.4 (Section 24.1) for the capacitance of a cylindrical capacitor then reduces to Eq. (24.2), the equation for the capacitance of a parallel-plate capacitor, with A being the surface area of...