Use the following data to calculate the standard enthalpy of
formation of solid strontium carbonate
SrCO3 (s) → SrO (s) +
CO2(s) ΔH° = 234 kJ/mol
ΔHf° of CO2 (g) = -394
kJ/mol ΔHf° of SrO(s) = -592
kJ/mol
A) -752 kJ
B) 752 kJ
C) -1220 kJ
D) -1812 kJ
E) 1812 kJ
f) 1220
Given:
ΔHo rxn = 234.0 KJ/mol
Hof(SrO(s)) = -592.0 KJ/mol
Hof(CO2(g)) = -394.0 KJ/mol
Balanced chemical equation is:
SrCO3(s) ---> SrO(s) + CO2(g)
ΔHo rxn = 1*Hof(SrO(s)) + 1*Hof(CO2(g)) - 1*Hof( SrCO3(s))
234.0 = 1*(-592.0) + 1*(-394.0) - 1*Hof(SrCO3(s))
Hof(SrCO3(s)) = -1220 KJ
Answer: C
Use the following data to calculate the standard enthalpy of formation of solid strontium carbonate SrCO3...
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