Question

Use the following data to calculate the standard enthalpy of formation of solid strontium carbonate SrCO3...

Use the following data to calculate the standard enthalpy of formation of solid strontium carbonate

SrCO3 (s) → SrO (s) + CO2(s)     ΔH° = 234 kJ/mol
ΔHf° of CO2 (g) = -394 kJ/mol       ΔHf° of SrO(s) = -592 kJ/mol

A) -752 kJ

B) 752 kJ

C) -1220 kJ

D) -1812 kJ

E) 1812 kJ

f) 1220

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Answer #1

Given:

ΔHo rxn = 234.0 KJ/mol

Hof(SrO(s)) = -592.0 KJ/mol

Hof(CO2(g)) = -394.0 KJ/mol

Balanced chemical equation is:

SrCO3(s) ---> SrO(s) + CO2(g)

ΔHo rxn = 1*Hof(SrO(s)) + 1*Hof(CO2(g)) - 1*Hof( SrCO3(s))

234.0 = 1*(-592.0) + 1*(-394.0) - 1*Hof(SrCO3(s))

Hof(SrCO3(s)) = -1220 KJ

Answer: C

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