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Methane (CH4) burns in air to form carbon dioxide and water as shown below. CH4(g) +...

Methane (CH4) burns in air to form carbon dioxide and water as shown below.

CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(l)

If a sample of methane occupies 426. mL at 2.31 atm, what volume (in mL) of oxygen gas at the same temperature and pressure is required to complete the reaction?

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Answer #1

From balanced reaction,

Mol of O2 required = 2*mol of CH4 reacting

So,

Volume of O2 required = 2* Volume of CH4 reacting

= 2*426 mL

= 852 mL

Answer: 852 mL

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