Calculate the enthalpy change for the reaction
NO(g) + O(g) → NO2(g)
from the following data
NO(g) + O3(9) → NO2(g) + O2(g) ΔH=-198.9 kJ/mol
O3(g) → 1.5O26(g) ΔH=-142.3 kJ/mol
O2(g) → 2O(g) ΔH = 495.0 kJ/mol
A. 153.8 kJ B. 190.9 kJ C.-551.6 kJ D.-304.1 kJ E. 438.4 kJ
Calculate the enthalpy change for the reaction NO(g) + O(g) → NO2(g)
Question 62 Calculate the enthalpy change for the following reaction: NO(g) + O(g) - NO2(g) from the following data: NO(g) + O3(g) – NO2(g) + O2(g) O3(g) – 1.502(g) O2(g) - 20(g) AH = -198.9 kJ AH = -142.3 kJ AH = 495.0 kJ 0-304.1kJ 438.4 kJ 190.9 kJ 153.8 kJ O -551.6 kJ
5) Calculate the enthalpy change for the reaction NO(g)+ Og) NO2g) from the following data: NOg) +03(g)-NO2(g) + O2(g) ΔΗ--I 98.9 kJ O3g) 1.502(g) 02(g) 20(g) AH-142.3 kJ AH = 495.0 kJ A) 153.8 kJ B) 438.4 kJ C)-551.6 kJ D) 190.9 kJ E)-304.1 kJ
physical chemistry 2. The bond dissociation energy of oxygen gas is 495 kJ/mole, while the enthalpy of formation of ozone gas (O3(g))is 142.3 kJ/mole. For the reaction: NO +O3(g) NO2(g) + O2(g) it is found that AH = -198.9 kJ/mole, Determine the enthalpy change for the reaction: NO(g) + O() NO2(8)
I'm really focused on getting an explanation with this so I can do the rest of them, so if you could explain and answer that would be great. Given the following thermochemical equations, NO(g) + O3(g) → NO2(g) + O2(g) where Δ H = −198.9 kJ/mol O3(g) → 3 2 O2(g) where Δ H = −142.3 kJ/mol O2(g) → 2O(g) where Δ H = +495 kJ/mol Determine the enthalpy change for the reaction: 2NO2(g) → 2NO(g) + O2(g)
Consider the following chemical reaction. NH3(g) + 2 O2(g) → HNO3(aq) + H2O(l) Calculate the change in enthalpy (ΔH) for this reaction, using Hess' law and the enthalpy changes for the reactions given below. (1a) 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(l); ΔH = −1166.0 kJ/mol (2a) 2 NO(g) + O2(g) → 2 NO2(g); ΔH = −116.2 kJ/mol (3a) 3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g); ΔH = −137.3 kJ/mol
Calculate the standard enthalpy of formation of NO(g) (in kJ/mol) from the following data. N2(g) + 2 O2(g) → 2 NO2(g) ΔH⁰298 = 66.4 kJ 2 NO(g) + O2(g) → 2 NO2(g) ΔH⁰298 = −116.2 kJ
Calculate the standard enthalpy change for the reaction 2C8H18(l) + 17O2(g) →16CO(g) + 18H2O(l). Given 2C8H18(I) + 25O2(g) →16CO2(g) + 18H2O(I) ΔH°=-11,020 kJ/mol 2CO(g) + O2(g) → 2CO2(g) ΔH° = -566.0 kJ/mol 0 -6,492 kJ/mol 15,550 kJ/mol 10,450 kJ/mol -10.450 kJ/mol 6,492 kJ/mol
Given the following data: 2O3(g) 3O2(g) -427 kJ O2(g) 2O(g) 495 kJ NO(g) + O3(g) NO2(g) + O2 -199kJ Calculate (in kJ) for the reaction: NO(g) + O(g) NO2(g)
a) Use Hess's law to calculate the enthalpy change for the reaction: 3C(s) + 4H2(g) + ½O2(g) → C3H8O(l) Given the following thermochemical equations: 2C3H8O(l) + 9O2(g) → 6CO2(g) + 8H2O(l) ΔH = -4042.6 kJ/mol C(s) + O2(g) → CO2(g) ΔH = -393.51 kJ/mol H2(g) + ½O2(g) → H2O(l) ΔH = -285.83 kJ/mol (in kJ/mol) A: -267.7 B: -302.6 C: -341.9 D: -386.3 E: -436.5 F: -493.3 G: -557.4 H: -629.9 b) Define if the following statement is an endothermic process or exothermic...
TC04M01 Use the enthalpy changes given in the data below to calculate the enthalpy change for this reaction: Cus(s) + O2(g) → Cu(s) + SO2(9) Data: Reaction no. Reaction A.HⓇ/kJ morat 298K standard state = 1 bar. +314 2 2 CuO(s) – 2Cu(s) + O2(g) S(s) + O2(g) - S02(9) 2CuO(s) + 2S(s) - 2CuS(s) + O2(9) -297 +208 Select one: a. +225 kJ/mol b.-85 kJ/mol O C. -244 kJ/mol d. -191 kJ/mol e. -225 kJ/mol