Given the following free energies of formations;
ΔGfo (kJ/mol)
C2H2 (g) 209.2
C2H6 (g) -32.9
calculate Kp at 298 K for C2H2(g) + 2 H2(g) → C2H6 (g)
A. 9.07x10-1
B. 97.2
C. 1.24x1031
D. 2.72x1042
E. None of these
The equilibrium constant of a system, K, can be related to the standard free energy change, ΔG∘ ΔG∘=−RTlnK where T is a specified temperature in kelvins (usually 298 KK) and R is equal to 8.314 J/(K⋅mol) Under conditions other than standard state, the following equation applies: ΔG=ΔG∘+RTlnQ In this equation, Q is the reaction quotient and is defined the same manner as KK except that the concentrations or pressures used are not necessarily the equilibrium values. Part A Acetylene, C2H2,...
Consider the following values of standard enthalpies and free energies of formation at 298 K: Chemical Species C2H2(g) C2H6(g) AH (kJ mol-') +228 -84 AGI° (kJ moll) +211 -32 Determine whether the reaction: C2H2(g) + 2 H2(g) → C2H6(g) is: • spontaneous and exothermic • spontaneous but endothermic • non-spontaneous and exothermic • non-spontaneous but endothermic Show your working
Acetylene, C2H2, can be converted to ethane, C2H6, by a process known as hydrogenation. The reaction is C2H2(g)+2H2(g)?C2H6(g) Given the following data, what is the value of Kp for this reaction? Substance ?G?f (kJ/mol) C2H2(g) 209.2 H2(g) 0 C2H6(g) ?32.89 In Part A, we saw that ?G?=?242.1 kJ for the hydrogenation of acetylene under standard conditions (all pressures equal to 1 atm and the common reference temperature 298 K ). In Part B, you will determine the ?G for the...
Calculate K at 298 K for the following reaction given the Gibbs free energy of formations 213) substance! ΔG。 kJ/mol N2O4(g) +99.8 NO2(g)+51.3 1.13 0.32 3.1
Based on the standard free energies of formation, which of the following reactions represent a feasible way to synthesize the product? A. 2C(s)+H2(g)→C2H2(g); ΔG∘f=209.2 kJ/mol B. N2(g)+3H2(g)→2NH3(g); ΔG∘f=−33.30 kJ/mol C. 2C(s)+2H2(g)→C2H4(g); ΔG∘f=68.20 kJ/mol D. 2SO(g)+O2(g)→2SO2(g); ΔG∘f=−600.4 kJ/mol Drag the appropriate items to their respective bins: Feasible Synthesis, or Non-feasible Synthesis
I solved A but I'm confused on how to solve B if someone could please help me I would highly appreciate it Acetylene, C2H2, can be converted to ethane, C2H6, by a process known as hydrogenation. The reaction is C2H2(g) + 2H2(g) = C2H6(g) Given the following data at standard conditions (all pressures equal to 1 atm and the common reference temperature 298 K), what is the value of Kp for this reaction? Substance AG: (kJ/mol) 209.2 C2H2(g) H2(g) C2H6(g)...
Consider the following hypothetical reaction at 310 K. Standard free energies of formation are given in parentheses. B C G° = –46.0 kJ/mol (?) (176.4 kJ/mol) Calculate the standard free energy of formation of compound B. a) 222.4 kJ/mol b) –222.4 kJ/mol c) 130.4 kJ/mol d) –130.4 kJ/mol e) none of these Please show work
Based on the standard free energies of formation, which of the following reactions represent a feasible way to synthesize the product? Drag the appropriate items to their respective bins. Reset Help 2Na(s) + O2(g) +Na2O2(s) AGE = -451.0 kJ/mol 2CO(g) + O2(g)+2C02(g) AGE = -788.0 kJ/mol N2(g) + O2(g) +2NO(g) AGE = 173.2 kJ/mol 2C(s) + H2(g) +C2H2(g) AGE = 209.2 kJ/mol Feasible synthesis Not a feasible synthesis
(a) Use the data given below and calculate ∆Ho, ∆So, ∆Go, and Kp at 25° C for the reaction: C2H2 (g) + 2 H2 (g) → C2H6 (g) (b) Calculate ∆G for the reaction at 250 °C. (c) At what temperature (°C) is ∆G equal to zero? In what temperature range is this reaction productfavored? Compound ∆ Ho , kJ/mol S o , J/mol• K C2H2 (g) 226.73 200.94 H2 (g) 0 130.68 C2H6 (g) -84.68 229.6
(a) Use the data given below and calculate ∆Ho, ∆So, ∆Go, and Kp at 25° C for the reaction: C2H2 (g) + 2 H2 (g) → C2H6 (g) (b) Calculate ∆G for the reaction at 250 °C. (c) At what temperature (°C) is ∆G equal to zero? In what temperature range is this reaction productfavored? Compound ∆ Ho , kJ/mol S o , J/mol• K C2H2 (g) 226.73 200.94 H2 (g) 0 130.68 C2H6 (g) -84.68 229.6