Identify the reduced substance, the oxidized substance, the reducing agent, and the oxidizing agent in the reaction of zinc with copper ions.
Zn(s)+Cu2+(aq)⟶Zn2+(aq)+Cu(s)
Answer:-
Zn(s) loses two electrons to form Zn2+ (aq). Thus, Zn is oxidized (oxidized substance) and it is the reducing agent.
Cu2+ (aq) gains two electrons to form Cu(s). Thus, Cu2+ is reduced (reduced substance) and it is the oxidizing agent.
Hence,
Zn(s) = oxidized substance
Cu+2 (aq) = reduced substance
Zn(s) = reducing agent
Cu+2 (aq) = oxidizing agent.
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