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Identify the reduced substance, the oxidized substance, the reducing agent, and the oxidizing agent in the...

Identify the reduced substance, the oxidized substance, the reducing agent, and the oxidizing agent in the reaction of zinc with copper ions.

Zn(s)+Cu2+(aq)⟶Zn2+(aq)+Cu(s)

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Answer #1

Answer:-

Zn(S) - Zn2+ (aq) + 2e- coxidation) Curt (aq) + 2e → Cu (s) (Reduction)

Zn(s) loses two electrons to form Zn2+ (aq). Thus, Zn is oxidized (oxidized substance) and it is the reducing agent.

Cu2+ (aq) gains two electrons to form Cu(s). Thus, Cu2+ is reduced (reduced substance) and it is the oxidizing agent.

Hence,

Zn(s) = oxidized substance

Cu​​​​​​​+2 (aq) = reduced substance

Zn(s) = reducing agent

Cu​​​​​​​+2 (aq) = oxidizing agent.

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