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Consider the following information. The lattice energy of NaCl is ΔH lattice=−788 kJ/mol The enthalpy of...

Consider the following information.

  • The lattice energy of NaCl is ΔH lattice=−788 kJ/mol

  • The enthalpy of sublimation of Na is ΔHsub=107.5 kJ/mol

  • The first ionization energy of Na is IE1=496 kJ/mol.

  • The electron affinity of Cl is ΔHEA=−349 kJ/mol.

  • The bond energy of Cl2 is BE=243 kJ/mol.

Determine the enthalpy of formation, ΔHf, for NaCl(s).

ΔHf= kJ/mol

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Answer #1

Lattice energy of NaCl = U -788 kJ/mol The enthalpy of sublimation of Na = S = 107.5 kJ/mol The ionization energy of Na = IE

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