Question

Write a balanced complete ionic equation for HCl(aq)+LiOH(aq)=H20(l)+LiCl(aq)

Answer 1

Molecular equation Lithium hydroxi de base (LiOH) reacts with the hydrochloric acid (HCI) to form lithium chlori de (KC1) and water (H2O) Molecular equation representing the reacti on between the LiOH and HCl is as follows LiOH(aq) + HCl (aq) -→ LiCl (aq) + H2O(1) Total ionic equati All the aqueous solutions split into their composite ions. Li. (aq) + C1-(aq) + H2O(1) ー→ Cancel the ions that are common on both sides of the equation to get the net ionic equati on. these ions are known as the spectator ions Here in this equati on, Li' and Cl are the spectator ions. 一→Li.faq) + Net ionic equati on: H(a OH(a)H,O()

Answer 2

The given reaction is between ethanoic acid and potassium carbonate (base). The ionic form of the reaction may be written by dissociating the various aqueous species into their corresponding ons The balanced chemical equation 2CH.COOH (M)-K.CO㈣ → 2CH.COOK.aq) + CO2(g)-H9,) Writing in ionic form: a(ag) (aq) 3 (ag) (ac) (aq) 21g) The net ionic equation maybe written by canceling the identical terms on both the sides of the equation 3 (ag) 2(8)

Answer 3

K2SO4 ------------------> 2K+ + SO4^2-

So to write the total ionic equation expand out all the (aq) compounds

1)
molecular equation
K2SO4(aq) + CaI2(aq) --------> CaSO4 (s) + 2KI (aq)

total ionic equation

2K+(aq) + SO4^2-(aq) + Ca2+(aq) + 2I-(aq) ------> CaSO4(s) + 2K+(aq) + 2I-(aq)

now, you can see that there are 2I-(aq) and 2K+(aq) on each side of the eqation. They have not changed at all, either their charge or their state (s,l,g,aq). These are the spectator ion, they do not participate in the reaction. So they are left ot of the total ionic eqation

SO4^2-(aq) + Ca2+(aq) -------> CaSO4(s)