A solution containing 27.55 mg of an unknown protein per 25.0 mL of solution was found to have...
Homework Answers
n=(3.22mmHg*.025L)/(62.36367*298K)
n=4.33*10^-6 mol
.02755g/4.33*10^-6 mol=6,360.25 g/mol
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A solution containing 27.55 mg of an unknown protein per 25.0 mL of solution was found to have...
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