How would you prepare 10 mL of a 0.25 M HCl solution if 1 M HCl was available?

Question

Question

How would you prepare 10 mL of a 0.25 M HCl solution if 1 M HCl was available?
How much 1 M HCl is needed? How much distilled water is used?

Answer 1

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Answer #1

M₁*V₁= M₂*V₂

M₁= 0.25 M

V₁= 10 mL

M₂= 1 M

V₂=M₁*V₁/ M₂= 0.25 x 10 / 1 = 2.5 mL

In order to prepare 10 mL of 0.25 M HCl solution, you need dilute 2.5 mL of 1M HCl to 10 mL by adding (10 mL - 2.5 mL = 7.5 mL) water to it.

answered by: Jenine

Answer 2

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