Question

Liquid hexane

CH3CH24CH3

reacts with gaseous oxygen gas

O2

to produce gaseous carbon dioxide

CO2

and gaseous water

H2O

. If

13.8g

of water is produced from the reaction of

77.56g

of hexane and

104.0g

of oxygen gas, calculate the percent yield of water.

Round your answer to

3

significant figures.

Answer 1

Q CH₂ (CH ₂ CH 4 19 0 6 CO₂ + +H₂O First of all , find out Moles of Ho actual) = Moles of Hexane = the limiting reagent. 13.8/18- 0.16 mil 77.56 -0.90 Moles of a = 104 3-25 CHz (CH)Chy + 19 Q = 6607 + 7H30. 0.90 3.25 Molet Laudat 1912 0.90 -0.90 3.25 -0.34 O act as limiting reagent By 19 moly of a Imoles of watu is formed similarly by Imol. of a = 1 - By .. 3.25 mol of Od - 14 x 3.25 = 2.39 mol- Percent Yield - Actual Yield x 100 Theoretical field x 100 = 32:01: 2.39 - = 32:14: 0.76 Page No.