Question

The value of Ksp for silver sulfate, Ag2SO4, is 1.20x10-5 . Calculate the solubility of Ag2SO4 in grams per liter. Exp...

The value of Ksp for silver sulfate, Ag2SO4, is 1.20x10-5 . Calculate the solubility of Ag2SO4 in grams per liter.
Express your answer numerically in grams per liter.
Solubility=
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Answer #1
Concepts and reason

The concept used in this problem is based on the solubility product.

Solubility product comes into action when the sparingly soluble (not totally dissolved) ionic compound dissociates into its constituent ions in water.

Fundamentals

Solubility product:

The solubility product helps to determine the solubility of the compound in water.

Higher the value of solubility product, higher will be the solubility of that compound in water.

Example-

А,В,
aА* + bB

The expression for the solubility product will be shown below.

sp
…… (1)

Here, [A]
is the concentration of [AJ
and[B
is the Concentration of [B
, a and b are the coefficients of the respective ion.

The reaction of silver sulfate in water is shown below.

2Ag SO
Ag2SO

Let the value of solubility of silver sulfate be s mol L

Ag,SO
2Ag SO,
2s

Similar to the solubility product expressed in equation (1), the expression for solubility product for silver sulfate will be shown below.

sp

Substitute 1.20x10
as the value of К.
яр
and 2s
as the value of [Ag]
and as the value of [so,]
4
.

1.20x10 [2s][s]
1.20x10 4s3
1.20x10
4
0.0144 mol.L =S

Conversion of the unit of solubility from mol per liter to gram per liter is as shown below.

M xs (mol.L1)
s (g.L
…… (2)

Substitute 0.0114 mol.L
as the value of s(mol.L
and 311.79 g.mol
as the value of the molar mass of silver nitrate (M) in equation (2)

s 311.79 g.mof x0.0144 nol.L)
s 4.49 g.L
=

Ans:

The solubility of silver sulfate in gram per liter is4.49 g.L
.

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