The emission line used for zinc determinations in atomic emissionspectroscopy is 214 nm. If there are 6.00×1010atoms of...
Homework Answers
E = hv
= hc/λ
=6.62*10-34 *3*108/214*10-9
= 9.28*10-19 J
For 6.00×1010 atoms of zinc
E = 6.00×1010 * 9.28*10-19
= 5.57*10-8 J
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