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The emission line used for zinc determinations in atomic emissionspectroscopy is 214 nm. If there are 6.00×1010atoms of...

The emission line used for zinc determinations in atomic emissionspectroscopy is 214 nm. If there are 6.00×1010atoms of zinc emitting light in the instrument flame at any giveninstant, what energy (in joules) must the flame continuously supplyto achieve this level of emission?
(Answer must be inJoules)
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Answer #1
For a zinc atoms
E = hv
   = hc/λ
   =6.62*10-34 *3*108/214*10-9
   = 9.28*10-19 J
For 6.00×1010 atoms of zinc
E = 6.00×1010 * 9.28*10-19
   
= 5.57*10-8 J
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