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The normal boiling point of a liquid is 282 °C. At what temperature (in °C) would...

The normal boiling point of a liquid is 282 °C. At what temperature (in °C) would the vapor pressure be 0.4 atm? (∆Hvap = 28.5 kJ/mol)

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11 P is te Vapoar PYessure ad a tempuratuve temperadare T is the Vapour Pressure at Kelvin T17, are in Hur Enthelpy of vapoavPh= (atm Tre 2824 273 = 2824373= 555 K O-Yath DHuap latm X 8.31y 3 hat 5ss AHot -X SS5 98-9 X103-mal - 0.000267297 55s J 0-0

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