A soccer ball is kicked from the ground with an initial velocity of 25m/s at an angle of 40 degrees with the horizontal. Determine how long the ball will stay in the air, before hitting the ground.
Horizontal velocity= 25cos40
vertical velocity=25 sin40
applying s=ut+0.5at2 in vertical direction
0=(25sin40)t+0.5(-g)t2
t=(25sin40)/0.5g=3.2795sec
SOLUTION
Vertical component of initial velocity = uV = 25 sin(40) = 17.67767 m/s
Now, as ball goes up against gravity, velocity decreases at the rate of g = 9.8 m/s^2
=> v = uV - 9.8 t
At maximum height, velocity = 0
=> 0 = 17.67767 - 9.8 t
=> t = time to reach maximum height = 17.67767/9.8 = 1.80 sec.
Time to come down to ground = time taken to reach maximum height = 1.80 sec
So,
Total time ball is in air
= time to go up + time to come down
= 1.80 + 1.80
= 3.60 sec. (ANSWER).
SOLUTION
Vertical component of initial velocity = uV = 25 sin(40) = 16.07 m/s
Now, as ball goes up against gravity, velocity decreases at the rate of g = 9.8 m/s^2
=> v = uV - 9.8 t
At maximum height, velocity = 0
=> 0 = 16.07 - 9.8 t
=> t = time to reach maximum height = 16.07/9.8 = 1.64sec.
Time to come down to ground = time taken to reach maximum height = 1.64 sec
So,
Total time ball is in air
= time to go up + time to come down
= 1.64 + 1.64
= 3.28 sec. (ANSWER).
A soccer ball is kicked from the ground with an initial velocity of 25m/s at an...
A soccer ball is kicked from the ground with an initial speed of 17.6m/s at an upward angle of 42.5 degrees. A player 49.4 m away in the direction of the kicks starts running to meet the ball at that instant. What must be his average speed if he is to meet the ball just before it hits the ground? Neglect air resistance.
A soccer ball is kicked with an initial horizontal velocity of 18 m/s and an initial vertical velocity of 13 m/s. 1) What is the initial speed of the ball? 2) What is the initial angle ? of the ball with respect to the ground? 3) What is the maximum height the ball goes above the ground? 4) How far from where it was kicked will the ball land? 5) What is the speed of the ball 0.8 seconds after...
A soccer ball is kicked with an initial horizontal velocity of 20 m/s and an initial vertical velocity of 16 m/s. I've calculated: Initial Speed: 25.61 m/s Angle: 38.66 degrees Maximum Height it reaches: 13.06 m Distance kicked: 65.29m NOW I NEED: What is the speed of the ball 0.7 seconds after it was kicked? How high above the ground is the ball 0.7 seconds after it is kicked? help? please.
A soccer ball is kicked at an angle of 40o from the ground at a speed of 30 m/s. a) Describe which motion (horizontal of vertical) of the ball is constant and which is accelerated. b) What are the vertical and horizontal components of the ball's initial velocity? c) For what length of time is the ball in the air assuming the ground is flat and horizontal? d) What is the range of the ball assuming the ground is flat...
a soccer ball is kicked with a speed of 9.20m/s at an angle of 55 degrees above the horizontal. if the ball lands at the same level from which it was kicked, how long was it in the air?
A soccer ball is kicked from the ground with an initial speed of 19.5 m/s at an upward angle of 45°. A player 55 m away in the direction of the kick starts running to meet the ball at that instant. What must be his average speed if he is to meet the ball just before it hits the ground?
A soccer ball is kicked with a speed of 9.25 m/s at an angle of 30.0 degrees above the horizontal. If the ball lands at the same level from which it was kicked, how long was it in the air?
A football is kicked from ground level with an initial velocity of 20.0 m/s at angle of 37.5° above the horizontal. How long is the football in the air before it hits the ground? Ignore air resistance.
A football is kicked from ground level with an initial velocity of 21.0 m/s at angle of 54.5° above the horizontal. How long, in seconds, is the football in the air before it hits the ground? Ignore air resistance.
Question: A soccer ball is kicked from ground level and sent toward a wall with a velocity of 14 m/s at an angle of 34.4 degree above the horizontal. The wall is 3.99 m away from the kicker. a. How long does it take the ball to reach the wall? b. how high is the ball when it hit the wall?
> There is a calculation error, 25 sin(40) = 16.07 m/s and not 17.67767. So final answer would be 3.28 sec and not 3.60 sec. Please see the correct answer in the next answer by me.
Tulsiram Garg Fri, Nov 26, 2021 7:50 AM