Question

A particle with positive charge q = 4.01 10^-18 C moves with a velocity

v

= (5î + 5ĵ − ) m/s through a region where both a uniform magnetic field and a uniform electric field exist.

(a)

Calculate the total force on the moving particle, taking

B

= (5î + 2ĵ + ) T and

E

= (3î − ĵ − 2) V/m. (Give your answers in N for each component.)

F_x= NF_y= NF_z= N

(b)

What angle does the force vector make with the positive x-axis? (Give your answer in degrees counterclockwise from the +x-axis.)

° counterclockwise from the +x-axis

(c)

What If? For what vector electric field would the total force on the particle be zero? (Give your answers in V/m for each component.)

E_x= V/mE_y= V/mE_z= V/m

Answer 1

Answert A) = Total force fa q Coxo) + ] F = 4.01 X1018 [V x3 + ²) J x B = j î û he = 72 - 10 - 15 f= 4.01 2018 Eî-101-15 R + 3 2 - - 2k) = 40 x1018 [102-11g - 17 fe] N

B) 1F1 = 5 Cros?t (1157+ (1352 = 22.68* 4.olxin16 Angle with x axis Cos L = (4.01x1018) X10 29.58 x4.01x2018

Coba lost=0.4428 La Cost ouuar = 63,7° I direction cosine () et force will zero il Magnetic force opposite to electric force Hence = q (UAB) = QE E= (V x B)
net force can only be zero if magnetic fore is opposite to the electric force