Question

Use the work–energy theorem to solve each of these problems. You can use Newton’s laws to...

Use the work–energy theorem to solve each of these problems. You can use Newton’s laws to check your answers.

A)

A skier moving at 5.57 m/s encounters a long, rough, horizontal patch of snow having a coefficient of kinetic friction of 0.220 with her skis. How far does she travel on this patch before stopping?

Express your answer with the appropriate units.

B)

Suppose the rough patch in part A was only 2.99 m long. How fast would the skier be moving when she reached the end of the patch?

Express your answer with the appropriate units.

C)

At the base of a frictionless icy hill that rises at 25.0∘ above the horizontal, a toboggan has a speed of 11.9 m/s toward the hill. How high vertically above the base will it go before stopping?

Express your answer with the appropriate units.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Guiven from gwen data a) Ake = -my? --Mv2 =-M(5.37) - 15:512 M mysz . wolk = thing a 2-0220 M X9.8 vd wek = AKE + MX15-512 =

Add a comment
Know the answer?
Add Answer to:
Use the work–energy theorem to solve each of these problems. You can use Newton’s laws to...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Use the work–energy theorem to solve each of these problems. You can use Newton’s laws to...

    Use the work–energy theorem to solve each of these problems. You can use Newton’s laws to check your answers. A)A skier moving at 4.25 m/s encounters a long, rough, horizontal patch of snow having a coefficient of kinetic friction of 0.220 with her skis. How far does she travel on this patch before stopping? B)Suppose the rough patch in part A was only 2.89 m long. How fast would the skier be moving when she reached the end of the...

  • A 62.0 kg skier is moving at 6.50 m/s on a frictionless, horizontal snow covered plateau when she encounters a rough patch 3.50 m long

    A 62.0 kg skier is moving at 6.50 m/s on a frictionless, horizontal snow covered plateau when she encounters a rough patch 3.50 m long. The coefficient of kinetic friction between this patch and returning to friction-free snow, she skis down an icy, frictionless hill 2.50 m high. (a) How fast is the skier moving when she gets to the bottom of the hill? (b) How much internal energy was generated in crossing the rough patch?

  • 12. A 62 kg skier is moving at 6.5 m/s on frictionless horizontal snow-covered plateau when...

    12. A 62 kg skier is moving at 6.5 m/s on frictionless horizontal snow-covered plateau when she encounters a rough patch 3.50 m long. The coefficient of kinetic friction between this patch and her skis is 0.30. After crossing the rough patch and returning to friction free snow, she skis down an icy frictionless hell 2.5 m high. A) How much work is done by friction in crossing the patch? B) How fast is the skier moving when she gets...

  • Need the exercise portion Hit the Ski Slopes EXAMPLE 5.8 GOAL Combine conservation of mechanical energy...

    Need the exercise portion Hit the Ski Slopes EXAMPLE 5.8 GOAL Combine conservation of mechanical energy with the work-energy theorem involving friction on a horizontal surface. h = 20.0 m у A skier starts PROBLEM from rest at the top of a frictionless incline of height (В С) 20.0 m, as in the figure. At the bottom of the incline, the skier The skier slides down the slope and onto a level surface, stopping after encounters a horizontal traveling a...

  • of work on the sand the sled is 0.133. The horizontal. The co 2. (35 pts) Use work-cnergy theorem to solve this pro...

    of work on the sand the sled is 0.133. The horizontal. The co 2. (35 pts) Use work-cnergy theorem to solve this problem. A sled (m 35.4 kg) slides down a hill that is angled at 21.2° above the horizontal. The coefficient of Kinetic friction between the hill and the sled is 0.133. The hill is .50 m long Air resistance docs -18,03 of work on the sled. A) Find the work done by the other forces acting on the...

  • PHYS 201-002 General Physics Fall 2018 <HW Set #5: Chapter 6 Problems Problem 6.53 Part A...

    PHYS 201-002 General Physics Fall 2018 <HW Set #5: Chapter 6 Problems Problem 6.53 Part A Constants A 66-kg skier starts from rest at the top of a 1200-m-long trail which drops a total of 210 m from top to bottom. At the bottom, the skier is moving 11 m/s How much energy was dissipated by friction? Express your answer to two significant figures and include the appropriate units 1.4.10 J Submit X Incorrect, Try Again; 2 attempts remaining <...

  • 2 55 pes) Use work energy theorem to solve 1650 kg) is at the soap of...

    2 55 pes) Use work energy theorem to solve 1650 kg) is at the soap of a menge there to solve this problem. A rocket powered sled ( pot a ll that is angled at 28. that is angleda alsave the horizontal. The coefficient concc friction between the constant chest of 175 and the sledis 0.136. The rockets on the sled provide a and the stad is 0.136. The rockets on SR The sled travels a da The sled travels...

  • A 4.5 kg box slides down a 4.2-m -high frictionless hill, starting from rest, across a...

    A 4.5 kg box slides down a 4.2-m -high frictionless hill, starting from rest, across a 2.2-m -wide horizontal surface, then hits a horizontal spring with spring constant 550 N/m . The other end of the spring is anchored against a wall. The ground under the spring is frictionless, but the 2.2-m-long horizontal surface is rough. The coefficient of kinetic friction of the box on this surface is 0.22. Part C How far is the spring compressed? Express your answer...

  • please draw a motion diagram and coordinate system thank you A skier is gliding along at...

    please draw a motion diagram and coordinate system thank you A skier is gliding along at 3.0 m/s on horizontal, frictionless snow. He suddenly starts down a 10° incline. His speed at the bottom is 20 m/s. What is the length of the incline? Express your answer with the appropriate units. CH HÅR O Units ? Value Submit Request Answer Part B How long does it take him to reach the bottom? Express your answer with the appropriate units. CHHA...

  • Problem 11.56 A 4.5 kg box slides down a 4.3-m -high frictionless hill, starting from rest,...

    Problem 11.56 A 4.5 kg box slides down a 4.3-m -high frictionless hill, starting from rest, across a 1.7-m -wide horizontal surface, then hits a horizontal spring with spring constant 550 N/m The other end of the spring is anchored against a wall. The ground under the spring is frictionless, but the 1.7-m-long horizontal surface is rough. The coefficient of kinetic friction of the box on this surface is 0.27. How far is the spring compressed? Express your answer to...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT