Question

Two masses are connected by a light string passing over a light frictionless pulley. The 5.00 kg mass is released from rest at a height of h = 4.00 m above the horizontal floor below.

(a) Using the law of conservation of energy, determine the speed of the 3.00 kg mass just as the 5.00 kg mass hits the ground.

(b) Use one of the sense-making techniques to analyze your solution to part (a). Clearly state which technique you’re using and why it is relevant.

(c) Find the maximum height to which the 3.00 kg mass rises after the 5.00 kg mass hits the ground. The image is not drawn to scale, assume that the 3.00 kg box does not hit the ceiling.

(d) Use a different sense-making technique than you used in part (b) to analyze your solution to part (c). Clearly state which technique you’re using and why it is relevant.

Answer 1

sopºtamia ser no 4m M2 = 3kg . Trifal Energy of the fiy delen is conserved Ź migh = meghe + s (mitm) V? 3 1549.814 4) = (399.8194)+(£*8** = 1962 = 117092 + 4ve P2 = 78 = 19-62 1V=4.429 m/s Jo & since many (mi) is falling from rest itt Intial velvety will be zero, &o its kinefie Energy at height n will be also Zero, 80 using conservation of energy ay it is referent ке) we - Мому “м о р һәм у ш щ моз Velocity Before coming to rest * = y = 4- 8) = 1 . 7 2x9081 So The to fee right well be they = 4+1 = 15m

o ID when "mi reached the maximum height The speed of mi is z ero $0 (ke); + \PE); = k Ef (Pty 7 I mine + migh = 0 + Might **(464g? +19-87x45 = {9+1* 4) → SO TH=sm) 7 Two maxx are connected by a single 1 String with no mechanical Advantage What ever distance the targer mans goes - down, the smaller mors will go up. , right at the instant the larger mas toucher The ground the smaller many will have gone up the same "Am' that the larger may went down.