Question

The figure shows an electron passing between two charged metal plates that create a 108 N/C vertical electric field perpendicular to the electron’s original horizontal velocity.

The figure shows an electron passing between two charged metal plates that create a 108 N/C vertical electric field perpendicular to the electron’s original horizontal velocity. (These can be used to change the electron’s direction, such as in an oscilloscope.) The initial speed of the electron is 3.3 × 106 m/s , and the horizontal distance it travels in the uniform field is 3.8 cm.

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Part (a): What is its vertical deflection in m?

Part (b): What is the vertical component of its final velocity in m/s?

Part (c): At what angle does it exit in degrees? Neglect any edge effects.


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Answer #1

Note-Since there is no force acts along x direction so throughout the motion x-component of velocity 3.3x10^6m/s remains same.

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