An electron is shot directly toward the center of a large metal plate that has surface...
An electron is shot directly toward the center of a large metal plate that has surface charge density - 1.00 × 10-6 C/m2. If the initial kinetic energy of the electron is 6.40 × 10-17 J and if the electron is to stop (due to electrostatic repulsion from the plate) just as it reaches the plate, how far from the plate must the launch point be?
Please explain your reasoning, thank you!
Homework Answers
electric field due to charge plate
E = sigma / epsilon_not
using energy equivalence
kinetic energy = q ( E d)
6.4*10^-17 = 1.6*10^-19* 10^-6* d / (8.85* 10^-12)
d = 3.54*10^-3 m
==========
do comment in case any doubt, will reply for sure.. Goodluck
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