A small 12.6 g plastic ball is tied to a very light 28.4 cm string that is attached to the vertical wall of a room. (See the figure (Figure 1).) A uniform horizontal electric field exists in this room. When the ball has been given an excess charge of -1.10μC , you observe that it remains suspended, with the string making an angle of 17.4° with the wall.
Part A
Find the magnitude of the electric field in the room.
Part B
Find the direction of the electric field in the room.
to the right
to the left
A small 12.6 g plastic ball is tied to a very light 28.4 cm string that is attached to the vertical wall of a room.
A small plasticl ball is tied to a very light 26.0 cm string that is attached to the vertical wall of a room. A uniform horizontal electric field of magnitude 36,000 N/C exists in this room. When the ball has been given an excess charge Q = -1.10 uC, you observe that the ball remains suspended, with the string making an angle of 17.4 degrees with the wall. A) What is the direction the electic field E in the room?...
A small 16.8 g plastic ball is suspended by a 20 cm long string in a 103 N/C uniform electric field directed at 45o with respect to the horizontal. If the ball is in equilibrium when the string makes a 20.0° angle with the vertical, what is the net charge on the ball?
A small, 2.00-g plastic ball is suspended by a 21.1-cm-long string in a uniform electric field as shown in the figure below. If the ball is in equilibrium when the string makes a 16.3° angle with the vertical, what is the net charge on the ball? E-1.00x103 N/C m=2.00 g
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A small m = 2.00 g plastic ball is suspended by a L = 16.0 cm long string in a uniform electric field, as shown in Figure P15.50. If the ball is in equilibrium when the string makes a 16.0° angle with the vertical as indicated, what is the net charge on the ball? __µC Figure P15.50 E=1.00×103 N/C
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A small 1.45 g plastic ball that has a charge q of 1.75 C is suspended by a string that has a length L of 1.00 m in a uniform electric field, as shown in the figure. If the ball is in equilibrium when the string makes a 9.80 angle with the vertical as indicated by θ, what is the electric field strength E?
A small 7 g plastic ball is suspended by a 22.4 cm long string in a uniform electric field 1140 N/C as shown. The ball is in equilibrium when the string makes a 26◦ angle with the vertical. A) What is the net charge q on the ball? The acceleration due to gravity is 9.8 m/s2 . Answer in units of µC. Doing it how I thought but its not taking my answer of 33.5423
A small 2.05 g plastic ball that has a charge q of 1.55 C is suspended by a string that has a length L of 1.00 m in a uniform electric field, as shown in the figure. If the ball is in equilibrium when the string makes a 9.80° angle with the vertical as indicated by 0, what is the electric field strength E? E = 2.45 x10–3 NICO