Question

Figure (a) shows a narrow charged solid cylinder that is coaxial with a larger charged cylindrical shell.


Figure (a) shows a narrow charged solid cylinder that is coaxial with a larger charged cylindrical shell. Both are nonconducting and thin and have uniform surface charge densities on their outer surfaces. Figure (b) gives the radial component E of the electric field versus radial distance r from the common axis. The vertical axis scale is set by Es = 4.5 x 103 N/C. What is the linear charge density of the shell? 

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Answer #1

A cylinder of radius just under r cm encloses only the solid cylinder and has an electric field of Es/3 at its surface.

Apply Gauss’s law:

2π(rcm)L(Es/3) = λL/e, where L is the length of the Gaussian cylindrical surface.

The L’s on both sides cancel, and one can solve for the charge per unit length, λ.

We get:

2π(rcm)(Es/3) = λ/e

=> λ = 2π(rcm)(Es/3)e

= 2π*r*(4.5 × 10^3/3)*(8.85*10^-12)

= 8.34*10^-8 r

[Plug in r to get the numerical value]

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