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A 75-m-long train begins uniform acceleration from rest. The front of the train has a speed...

A 75-m-long train begins uniform acceleration from rest. The front of the train has a speed of 18 m/s when it passes a railway worker who is standing 200 m from where the front of the train started. What will be the speed of the last car as it passes the worker?

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Answer #1

For the front car :

Vi = initial speed = 0 m/s

Vf = final speed as it cross the worker = 18 m/s

d = distance travelled = 200 m

a = acceleration

using the equation

Vf2 = Vi2 + 2 a d

(18)2 = (0)2 + 2 a (200)

a = 0.81 m/s2

for the last car :

d = distance travelled = 200 + 75 = 275 m

Vi = initial speed = 0 m/s

Vf = final speed

a = acceleration = 0.81 m/s2

using the equation

Vf2 = Vi2 + 2 a d

Vf2 = 02 + 2 (0.81) (275)

Vf = 21.11 m/s

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