A metal sphere centered at the origin has a surface charge density that has a magnitude of 24.9 nC/m2 and a radius less than 2.00 m. At a distance of 2.00 m from the origin, the electric potential is 530 V and the electric field strength is 265 V/m. (Assume the potential is zero very far from the sphere.) What is the radius of the metal sphere?
AS electric field is not zero th epoint of observation is beyond teh radius of the sphere. Let it be R.
So total charge,
Q is given by
Q = 4x3.14x24.9x10^-9R^2 = [3.12x10^-7]R^2 Coulomb
Potential,V at r distance away from centre is given by
V= 9x10^9x(3.12x10^-7xR^2)/2=530 (given).
So
(R^2 = 530/[1404]= .377or R =0.614 m
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