Vx is the velocity of a particle moving along the x axis as shown. If x = 1.0 m at t = 1.0 s, what is the position of the particle at t = 6.0 s?

Question

Question

V_xis the velocity of a particle moving along the x axis as shown. If x = 1.0 m at t = 1.0 s, what is the position of the particle at t = 6.0 s?

V (m/s) 4.0 3.0 2.0 1.0 0 +(s) 1.0 2.0 3.0 1.0 5.0 6.0 1.0 2.0

Answer 1

Answer #1

Given:position at t=1s(x1)=+1m

Area under the v-t graph tells about the displacement(position-difference).

So we will calculate the area from t=1s to t=6s.

Area below the x-axis is taken as negative.

Area=(0.5*2*1)-(0.5*2*1)-(0.5*3*2)=-3m

Displacement(x6-x1)=area=-3m

x6-1m=-3m >>>>x6=(-3+1)m

position of particle at t=6s, x6=-2m.

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Answer 2

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