An electric circuit consists of six resistors and a real battery with Emf = 9 V and an internal resistance r = 0.5ohm . Find the battery current and the terminal voltage of the battery
remember these about Combination of Resistors
if R1 and R2 are the resistances connected in series then effective resiatcne Rnet = R1+R2
if R1 and R2 are connected in parallel, then 1/Rnet =1/R1 +1/R2 or Rnet = R1R2/(R1+R2)
same current passes through each of the ressitor in series combination and
same votage passes through eacf of the resistor in parallel combination
apply ohms law V = iR
where V = volatge and i = current
so here
6ohms is in series with 6 ohms = 12 ohms
12 parallel with 8 ohms = 12*8/20 = 4.8 ohms
4.8 series with 4 ohms, 2 ohms , 4 ohms
Rnet = 14.8+0.5 = 15.3 ohms
so current i = V/R = 9/15.3
i = 0.588 AMps
-------------------------------------
Vt = e-iR
Vt = 9-(0.588 * 0.5)
Vt = 8.7 Volts
An electric circuit consists of six resistors and a real battery with Emf = 9 V...
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