A motorcycle is stopped at a traffic light. When the light turns green, the motorcycle accelerates to a speed of 71 km/h over a distance of 50 m.
a) What was the average acceleration of the motorcycle over this distance?
(b) Assuming the motorcycle maintained a constant acceleration, how far is it from the traffic light after 3.1 s?
(a) required equation is
v^2=u^2+2*a*s
u=0 m/s
v=71 km/h=(71*1000)/3600=19.72 m/s
s=50m
a=((v^2)-(u^2))/2*s
a= ((19.72^(2))-(0))/(2*50)
a=3.88 m/s^2
(b) given that a is constant& t=3.1s
so
s=u*t
s=19.72*3.1
s=61.13 m
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