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A 0.5-kg block slides among a horizontal frictionless surface at 2 m/s. It is brought to...

A 0.5-kg block slides among a horizontal frictionless surface at 2 m/s. It is brought to rest by compressing a very long spring of spring constant 800 N/m. What is the elastic potential energy stored in the block-spring system when the block is brought to rest?

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Answer #1

Here ,

as the energy stored in the spring is equal to the initial kinetic energy of the block when the block comes to rest

elastic potential energy stored in the block-spring system = 0.50 * m * v^2

elastic potential energy stored in the block-spring system = 0.50 * 0.50 * 2^2

elastic potential energy stored in the block-spring system = 1 J

the elastic potential energy stored in the block-spring system is 1 J

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