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At one instant, a 17.5-kg sled is moving over a horizontal surface of snow at 3.50 m/s. After...

At one instant, a 17.5-kg sled is moving over a horizontal surface of snow at 3.50 m/s. After 8.75 s has elapsed, the sled stops. Use a momentum approach to find themagnitude of the average friction force acting on the sled while it was moving.
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SOLUTION:

Mass of the sled, m=17.5 kg

Intial speed of the sled, u=3.50 m/s

Final spedd of the sled, v=0 m/s

Time intervel, t=8.75 s

From Newton's second law,

F=ma

=m(u-v)/t

=(17.5 kg)(3.50 m/s- 0 m/s)/(8.75 s)

= 7 N

answered by: prakash
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