SOLUTION:
Mass of the sled, m=17.5 kg
Intial speed of the sled, u=3.50 m/s
Final spedd of the sled, v=0 m/s
Time intervel, t=8.75 s
From Newton's second law,
F=ma
=m(u-v)/t
=(17.5 kg)(3.50 m/s- 0 m/s)/(8.75 s)
= 7 N
At one instant, a 17.5-kg sled is moving over a horizontal surface of snow at 3.50 m/s. After...
Question: At one instant, a 17.5-kg sled is moving over a horizontal surface of snow at 3.50 m/s. After 8.75 s has elapsed, the sled stops. Use a momentum approach to find the average friction force acting on the sled while it was moving. Please check my work. If it is incorrect please provide detail. Sled mass (m) = 17.5kg moving over a horizontal surface initial velocity of (U) = 3.5 m/s Initial momentum of the sledge (P1)=mU (P1)=(17.5kg)(3.50 m/s)...
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