Consider the following figure. (Assume V = 15 V, R1 = 2.6 Ω, and R2 =1.6Ω)

Question

Question

(a) Can the circuit shown above be reduced to a single resistor connected to the batteries? Explain.

(b) Calculate each of the unknown currents 11, I2, and I3 for the circuit. (Give the magnitude of the current only.)

Answer 1

Answer #1

Let us consider the direction of i2to be anticlockwise ( say)

Using KVL in upper loop

6.6 I1 + 3 I1 + 3i2 = 24

9.6 I1 + 3 I2 = 24... (i)

Using KVL in lower loop

3 I1 + 3 I2 + 6.6 I2 = - 15

3 I1 + 9.6 I2 = - 15... (ii)

Solving (i) and (ii)

I1 = 3.31 A

I2 = 2.597 A

I3 = 0.713 A

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Comment in case any doubt, will reply for sure.. Goodluck

Answer 2

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