Two stationary positive point charges, charge 1 of magnitude 3.45 nC and charge 2 of magnitude 1.60 nC, are separated by a distance of 44.0 cm. An electron is released from rest at the point midway between the two charges, and it moves along the line connecting the two charges.
Part A
What is the speed vfinal of the electron when it is 10.0 cm from charge 1?
Here ,
let the speed of the electron is v
Using conservation of energy
loss in potential energy = increase in kinetic energy
-9 *10^9 * 10^-9 * 1.602 *10^-19 * ( (3.45 + 1.60)/(0.22) - (3.45/0.10 + 1.60/0.34)) = 0.50 * 9.11 *10^-31 * v^2
solving for v
v = 7.17 *10^6 m/s
the speed of the electron is 7.17 *10^6 m/s
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