Question

What is the strength of the electric field at the position indicated by the dot in...

uploaded imageWhat is the strength of the electric field at the position indicated by the dot in the figure?

E = _____ N/C

What is the direction of the electric field at the position indicated by the dot in the figure? Specify the direction as an angle above the horizontal line.

θ = ____ ⁰

PLEASE SHOW ALL WORK

0 0
Add a comment Improve this question Transcribed image text
✔ Recommended Answer
Answer #1
Concepts and reason

The concept used to solve this problem is the electric field due a charged body.

Use the concept of coulomb’s constant, the charge on body, and the distance from the charged body to find the electric field due to x-component of force due to one charged particle.

Use the electric field due to x-component of force due to 1 charged particle to find the strength of the electric field by both the charges at the position indicated by dot.

Use the x-component of the net electric field to find the direction as an angle above the horizontal line.

Fundamentals

Write the expression for the electric field due to a charged body.

Here, the Coulomb’s constant is , the charge on body is , and the distance from the charged body is .

The figure below shows the distance between the charges and the dot.

-
- -
-
-
-
-
- -
-
5 cm
- -
5 v2
cm
-
- -
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
5 cm
-
-
5 v2 cm
X) ----------

The diagonal line joining the charges and the dot is 52 cm
.

The arrangement of charges with the dot is symmetric and is at equal distance with each other.

Both the charges are positive in nature and hence, they repel each other with the same magnitude. Therefore, y-component of the force is canceled. Hence, only the x-component of force will act on the dot.

Write the expression for the electric field due to x component of force due to one charged particle.

Substitute 8.987552x109 N.m/c
for , for and 512x102 m
for .

(8.987552x10)(10)
(512x102)
_(8.987552)
(50x104)
=1797.51 N/C

Write the expression for the x-component of the electric field due to charge.

cos 45º =

Here, the x-component of electric field is .

Substitute 1797.51 N/C
for .

cos 45º = 1797,51
E - 1797.51x cos 45º
E =1797.51x1
E =1271.03 N/C

The above value of electric field is due to the only on the dot.

Write the expression for the electric field due to both the charges.

E = 2E

Substitute 1271.03 N/C
for .

E = 2x1271.03
= 2542.06
2542 N/C

From the above step,

There is only x-component of the net electric field at the dot and hence, the direction of the electric field would be in x-direction and the angle above the horizontal line would be .

Ans:

The strength of the electric field at the position indicated by dot is 2542 N/C
.

Add a comment
Know the answer?
Add Answer to:
What is the strength of the electric field at the position indicated by the dot in...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT