x - component of the of the net force on particle 3 is,
F3x = F1x + F2x + F4x
the horizontal force due to charge q1 is zero ,so net force
F3x = 0 + F2*cos45 + F4x
Distance between charge q2 and q3
r23 = sqrt[(0.07)2 + (0.07)2]
r23 = 0.098 m
F3x = k*q2*q3*cos45/(r23)2 + k*q3*q4/(r34)2
F3x = 9*109*750*10-9*93*10-9*cos45/(0.098)2 + 9*109*93*10-9*93*10-9/(0.07)2
F3x = 0.0620 N
F3y = -F1y + F2y + F4y
F3y = -k*q1*q3/(r13)2 + k*q2*q3*sin45/(r23)2 + 0
F3y = 9*109*750*10-9*93*10-9/(0.07)2 + 9*109*750*10-9*93*10-9/(0.098)2
F3y= 0.1742 N
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