Use the formula Q = CV.
We can get the charge on the first capacitor: CV = (11.8 * 10-6 F)(12.0 V) = 1.42 * 10-4 C.
Now that charge is shared among two capacitors, and since we know the new voltage is 2.66 V, we can figure the new capacitance: C = Q/V = (1.42 * 10-4 C)/(2.66 V) = 5.32 * 10-5 F.
The formula for capacitors in parallel is to just add their individual capacitances. So we know:
C + (11.8 * 10-6 F) = 5.32 * 10-5 F
C = 4.14 * 10-5 F or 41.4 μF
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