Question

Problem 7: Two large rectangular sheets of charge of side L are separated by a distance d (d << L) have a surface charge density of 4.2 uC/m². Take +x to be to the right.

 Randomized Variables

 σ =4.2 μC/m

.

 Part (a) Enter the value of the electric field, in newtons per coulomb, at point A. Assume point A is 0.1 d from the surface of the left sheet.

 Part (b) Enter the value of the electric field, in newtons per coulomb, at point B. Assume point B is 0.25 d from the surface of the left sheet.

 Part (c) Enter the value of the electric field, in newtons per coulomb, at point C. Assume point C is 0.5 d from the surface of the left sheet.

 Part (d) Enter the value of the electric field, in newtons per coulomb, at point D. Assume point D is 0.1 d from the surface of the right.

Answer 1

Here ,

for the electric field due to a reactangular sheet , E

E = surface charge density/(2 * epsilon)

E = 4.2 *10^-6/(2 * 8.854 *10^-12)

E = 2.37 *10^5 N/C

part a)

net electric field at A = -(2.37 *10^5 + 2.37 *10^5)

net electric field at A = -4.74 *10^5 N/C

part B)

at B

net electric field at B = E - E

net electric field at B = 0 N/C

part C)

at C

net electric field at B = E - E

net electric field at B = 0 N/C

part D)

at D

net electric field at D = (2.37 *10^5 + 2.37 *10^5)

net electric field at D = 4.74 *10^5 N/C