40 mm apart, pair of charged conducting plates produces a uniform field of 12,000N/C directed to...
40 mm apart, pair of charged conducting plates
produces a uniform field of 12,000N/C directed to the right,
between the plates.
An electron is projected from plate A, directly toward plate B, with an initial velocity vo=1.0x107 m/s. The closest approach of the electron to plate B is
Homework Answers
Loss in kinetic energy = work done
Therefore ,
0.5*m*v^2 = charge of electron *field *distance travelled
0.5*9.11*10^-31*(1*10^7)^2 = 12000*1.6.10^-19*s
s = 23.7*10^-7 m = 24 mm.
So distance of closest approach = 40-24 = 16 mm
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