Question

A simple pendulum consists of a ball of mass 5.00kg hanging from a uniform string of mass 0.060 0 kg and length L. If the period of oscillation of the pendulum is 2.00 s, determine the speed of a trasverse wave in the string when the pendulum hangs vertically.

Answer 1

The Solution will be

The period of a simple pendulum. is T=2r/L/g. Thus, if this pendulum has a perioa o S, its length must be L=&T2= (9.80 m/s2)(2.00 s)2 2 9.80 m/s 2.000.993 m 4T The mass per unit length of the string is then mstring_ 0.0600k L 0.993 m 0.0604 kg /m When the pendulum hangs vertical and stationary, the tension in the string is F- mballg (5.00 kg 9.80 m/s2)- 49.0 N The speed of a transverse wave in the string under these conditions will be 49.0 N 0,0604 k / 28.5 m/s 0